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Using the ratio of perfect squares method, what is square root of 68 rounded to the nearest hundredth?

I don't know what the ratio of perfect squares method is. Could someone please help me?

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You have to find which two numbers divide number 68 and one of them has a square root that is an integer. So we have : 68 = 4 * 17 ( sqrt(4)=2)
Then sqrt(68) = sqrt(4 * 17) = sqrt(4)*sqrt(17)=2 * sqrt(17) =
=2*4.123=8.246. Rounded to the nearest hundredth it is 8.25.
This id the way you can find any square using perfect square method.
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