Question

In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?

Answer 1

`2 C_(6)H_(6) + 15O_(2) ----->\ \textgreater \ 12CO_(2) + 6H_(2)O`


`mol of benzene = (mass)/(Mr)`
=
`<span>(10.47g)/((6 * 12) (6 * 1) g/mol)`
= 0.134 mol

mol of oxygen:
ratio of
`C_(6) H_(6) : O_(2)`
= 2 : 15
= 1 : 7.5

: . mol of
`O_(2)` = 0.134mol * 7.5
= 1.01 mol

Mass of Oxygen = mol * Mr
= 1.01 mol * (16*2) g/mol
= 32.22g

Note: Mr is molar mass