Problem
find the equation of the line that passes through the point (3,-2) and is perpendicular to the line y=1/2x-2
Solution
For this case if we have two lines perpendicular we need to satisfy the following:
m1 * m2= -1
For this case m1= 1/2 and we can find m2 like this:
m2= -1/m1 = -1/ 1/2 = -2
And now we can use the point given (3,.2) in order to find the equation on this way:
-2 = -2 (3) +b
And solving we got:
b= -2 +6= 4
So then our equation would be:
y= -2x +4
And that would be the final solution