Question

Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth.

Answer 1

`3 x^(2) + x + 10 = 0`

`x = \frac{-b(+or-) \sqrt{ b^(2) - 4ac } }{2a}`

`x = \frac{-1(+or-) \sqrt{ 1^(2) - 4(3)(10) } }{2(3)}`
: . x = \frac{-1 + \sqrt{-119} }{6} OR
`x = (-1 - √(-119) )/(6)`

Thus the roots or the solutions to this equation are imaginary because the discriminant
`√(-119)` is negative and a negative number is undefined when rooted.