Question

What are the coordinates of the center of the circle if this is its equation:

x2 + y2 - 16x + 6y +53 = 0

Answer 1

Hello,

x²-16x+y²+6y+53=0
==>x²-2*8*x+8² + y²+2*3*y+3²+53-64-9=0
==>(x-8)²+(y+3)²=20
Center is (8,-3) and radius =√20