What are the coordinates of the center of the circle if this is its equation: x2 + y2 - 16x + 6y +53 = 0

asked Mar 21, 2017 227k views

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What are the coordinates of the center of the circle if this is its equation:

x2 + y2 - 16x + 6y +53 = 0

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Hello,

x²-16x+y²+6y+53=0
==>x²-2*8*x+8² + y²+2*3*y+3²+53-64-9=0
==>(x-8)²+(y+3)²=20
Center is (8,-3) and radius =√20

Mertaydin answered Mar 26, 2017

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