Answer:
D. 2058.24 in³
Explanation:
Let r,h be the radius and height of smaller can and R,H be the radius and height of larger can
Then, R=4r and H=4h
Volume of smaller can=32.16 in³
⇒ πr²h=32.16 in³
Volume of larger can= πR²H
= π(4r²)×4h
= 64πr²h
= 64×32.16 in³
= 2058.24 in³
Hence, correct option is:
D. 2058.24 in³