Question

1/3,0,1,-2 what are the next 3 terms of the sequence

Answer 1

Hello,

One solution may be

`a_(n+1)=a_(n)*(-3) +1`


`a_(0)=(1)/(3)`


`a_(1)=(1)/(3)*(-3) +1=0`

`a_(2)=0*(-3) +1=1`

`a_(3)=1*(-3) +1=-2`


`a_(4)=(-2)*(-3) +1=7`

`a_(5)=7*(-3) +1=-20`

`a_(6)=(-20)*(-3) +1=61`
...
REM:

`a_(n)=((-3)^(n))/(12)+(1)/(4)`