Question

What is the coefficient of x in the division (18x^3+12x^2-3x)/6x^2?

A.
3

B.
2

C.
-0.5

D.
-3

Answer 1

That would be A.... when you divide the trinomial in bracket by the
`6x^(2)` you will realize that the coefficient of the x is 3. If you want me to send a picture of the division please indicate.

Answer 2

3

Explanation:

Given :
`(18x^3+12x^2-3x)/(6x^2)`

To Find: What is the coefficient of x in the division

Solution:

`(18x^3+12x^2-3x)/(6x^2)`

On Dividing we

Quotient = 3x+2

Remainder = -3x

So, coefficient of x in quotient = 3

Thus the coefficient of x in the division
`(18x^3+12x^2-3x)/(6x^2)` is 3

Hence Option A is correct