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Which restriction is appropriate for the variable? 3y^2 - 3y/y-1 A. no restrictions are needed B. y= -1 C. y =1 D. y = 3 <---
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Which restriction is appropriate for the variable?

3y^2 - 3y/y-1

A. no restrictions are needed
B. y= -1
C. y =1
D. y = 3 <---

User Hachiko
by
8.6k points

1 Answer

2 votes
Best answer is y=1
Because if the denominator is equals to 1, then the answer will be undefined and we don't want it to be undefined.
User Tom Rini
by
8.4k points
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