Question

What is the slope of the line that passes through (3'-7)(-1'1)

Answer 1

To solve for slope. Remember that slope, m= (change in y)-(change in x). So that means m= (y2-y1)/(x2-x1). Putting in the values we get (1--7)=(1+7)/(-1-3)= (8)/(-4)= -2. So m, or slope is -2.

Answer 2

Slope of line passing through (3,-7) and (-1,1) = -2

Explanation:

The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by
`(y_2-y_1)/(x_2-x_1)`

Here points are given by (3,-7) and (-1,1)

So we have (x₁,y₁) = (3,-7) and (x₂,y₂) = (-1,1)

Slope
`=(1-(-7))/((-1)-3)=(8)/(-4) =-2`

Slope of line passing through (3,-7) and (-1,1) = -2