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What is the distance between points 5, 2 and 1, -3 on a coordinate plane?

User Kyiu
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1 Answer

25 votes
25 votes

ANSWER:

The distance is 6.4 units

Explanation:

We have the following points:


\begin{gathered} (5,2) \\ (1,-3) \end{gathered}

We have the formula to calculate the distance between two points in the Cartesanian plane is the following:


d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

Replacing:


\begin{gathered} d=\sqrt[]{\mleft(1-5\mright)^2+\mleft(-3-2\mright)^2} \\ d=\sqrt[]{(-4)^2+(-5)^2} \\ d=\sqrt[]{(16+25} \\ d=\sqrt[]{41} \\ d=6.4 \end{gathered}

User Deech
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