Question

A chess game comes with two kings, two queens, four rooks, fourbishops, four knights, and sixteen pawns. A game piece is randomlyselected, replaced, then another is chosen. Find the probability ofselecting a king or queen, then a pawn.

Answer 1

Given a chess game has the following:

2 kings

2 queens

4 rooks

4 bishops

4 knights

16 pawns

One game piece is randomly selected, replaced, the another is chosen.

Total number of game piece = 2 + 2 + 4 + 4 + 4 + 16 = 32

To find the probability of selecting a king or queen, then pawn, first find the probability of selecting a king or queen, and the probability of selecting a pawn.

We have:

`\begin{gathered} P(k\text{ or q) = }(2+2)/(32)\text{ = }(4)/(32)\text{ = }0.125 \\ \\ P(\text{pawn) = }(16)/(32)\text{ = }(1)/(2)\text{ = 0.5} \\ \\ \end{gathered}`

Now, let's P(king or queen) and P(pawn):

`P(k\text{ or q) and P(pawn) = 0.125 }\ast\text{ 0.5 = }0.0625`

Therefore, the probability of selecting a king or queen, then a pawn is 0.0625

ANSWER:

0.0625