Question

For what value of θ, in degrees, is sin θ = cos 58°?

Answer 1

Hope you can see and understand what I wrote

Answer 2

The value of
`\theta` is, 32 degree.

Explanation:

Given the equation:

`\sin \theta = \cos 58^(\circ)`

We have to find the value of
`\theta`

Using the rule:

`\cos (90-\theta) = \sin \theta`

then;

`\cos (90-\theta) = \cos 58^(\circ)`

Comparing both sides we have;

`90^(\circ)-\theta = 58^(\circ)`

Subtract 90 from both sides we have;

`-\theta = -32^(\circ)`

Simplify:

`\theta = 32^(\circ)`

Therefore, the value of
`\theta` is, 32 degree.