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What is the exact value of x in the exponential equation 2^8x − 3 = 7? x = log4/8log2 x = 1/8log2 x= 5/8 x =log5/8
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Feb 12, 2017
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What is the exact value of x in the exponential equation 2^8x − 3 = 7?
x = log4/8log2
x = 1/8log2
x= 5/8
x =log5/8
Mathematics
high-school
Samlandfried
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Hello,
2^(8x)-3=7
==>2^(8x)=10
==>8x log (2)=log(10)
==>8x log(2)=1
==>x=1/(8*log(2))
With parenthesis on the denominator, the answer is B.
Newspire
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Feb 18, 2017
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