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5 votes
What is the product?

2a-7 over a times 3a^2 over 2a^2-11a+14
a) 3 over a -2
b) 3a over a-2
c) 3a over a+2
d) 3 over a+2

User Merterpam
by
7.3k points

2 Answers

3 votes
this question involves factoring and multiplying equations so just follow along my procedures in the image
What is the product? 2a-7 over a times 3a^2 over 2a^2-11a+14 a) 3 over a -2 b) 3a-example-1
User Jonalv
by
6.8k points
1 vote

Answer:

The correct option is b.

Explanation:

We have to find the product of
(2a-7)/(a) and
(3a^2)/(2a^2-11a+14).

Multiply both terms.


(2a-7)/(a)* (3a^2)/(2a^2-11a+14)

Cancel out the common factor a from numerator and denominator.


(2a-7)/(1)* (3a)/(2a^2-7a-4a+14)


(2a-7)/(1)* (3a)/(a(2a-7)-2(2a-7))


(2a-7)/(1)* (3a)/((2a-7)(a-2))

Cancel out the common factor (2a-7) from numerator and denominator.


(1)/(1)* (3a)/(a-2)


(3a)/(a-2)

Therefore, the correct option is b.

User Haykart
by
7.4k points