318,465 views
40 votes
40 votes
Please help me with this quickly, please make it simple and easy I don’t understand any other tutors

Please help me with this quickly, please make it simple and easy I don’t understand-example-1
User Mmonem
by
2.9k points

1 Answer

9 votes
9 votes

ANSWER

40 meters per minute

Step-by-step explanation

We have to find the rate of the wind - in other words, the speed of the wind.

We know that the duck can fly 2400 m in 10 minutes with the wind, so the speed of the duck when it is flying with the wind is,


s_{with\text{ }the\text{ }wind}=(2400m)/(10min)=240m/min

However, when the duck is flying against the wind, it can only fly 2/3 of this distance in the same time, which is,


2400m\cdot(2)/(3)=1600m

So, the speed of the duck against the wind is,


s_{against\text{ }the\text{ }wind}=(1600m)/(10min)=160m/min

The speed of the duck with the wind is the sum of the actual speed of the duck and the speed of the wind,


s_{with\text{ }the\text{ }wind}=s_(duck)+s_(wind)

While the speed of the duck against the wind is the actual speed of the duck minus the speed of the wind,


s_{against\text{ }the\text{ }wind}=s_(duck)-s_(wind)

If we subtract the equation of the speed against the wind from the equation of the speed with the wind, we have,


\begin{gathered} s_{with\text{ }the\text{ }wind}-s_{against\text{ }the\text{ }wind}=s_(duck)-s_(duck)+s_(wind)-(-s_(wind)) \\ \\ s_{with\text{ }the\text{ }wind}-s_{against\text{ }the\text{ }wind}=0+s_(wind)+s_(wind) \\ \\ s_{with\text{ }the\text{ }wind}-s_{against\text{ }the\text{ }wind}=2s_(wind) \end{gathered}

Solving for the speed of the wind and replacing the values,


s_(wind)=\frac{s_{with\text{ }the\text{ }wind}-s_{against\text{ }the\text{ }wind}}{2}=(240m/min-160m/min)/(2)=(80m/min)/(2)=40m/min

Hence, the speed (or rate) of the wind is 40 meters per minute.

User Hektor
by
3.4k points