Question

Choose the equation that could be used to find three consecutive integers whose sum is 36.

n + (n + 2) + (n + 4) = 36

n + (n + 1) + (n + 3) = 36

n + (n + 1) + (n + 2) = 36

n + (n − 1) + (n − 3) = 36

Answer 1

n +(n+1) + ( n+2)=36
the third answer

Answer 2

Let

n--------> the first integer

n+1------> the second consecutive integer

n+2-----> the third consecutive integer

we know that

`n+(n+1)+(n+2)=36\\3n+3=36\\3n=36-3\\3n=33\\n=33/3\\n=11`

the numbers are

`11,12,13`

therefore

the answer is

The equation is
`n+(n+1)+(n+2)=36`