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Use the quadratic formula to solve 2y2 + 2y – 12 = 0.

Question 6 options:


{–3, –2}



{3, –2}



{–3, 2}


{3, 2}

User Bojan
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1 Answer

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Hello
y²+y-6=0
==> y²-2y+3y-6=0
==>y(y-2)+3(y-2)=0
==>y-2)(y+3)=0
==>y=-3 or y=2

Answer C (-3,2)
User Ben Hadfield
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