Question

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A)0.827
B)0.944
C)1.21
D)1.06

Answer 1

That answer is wrong it is not 1.21 just turned it in and was wrong

Answer 2

The equation for the index of refraction is n = sin(theta1)/sin(theta2) where theta1 is the refracted angle and theta2 is the angle in a medium. Plugging in the values for the index of refraction, n = sin(32)/sin(26) we get 1.21. the answer is letter C. The index of refraction is always greater than 1.