Final answer:
The specific heat capacity of a 3.1g ring that is heated with 10.0 calories causing a temperature rise of 17.9°C is approximately 0.1801 cal/g°C.
Step-by-step explanation:
To calculate the specific heat capacity of the ring, we use the formula:
q = mcΔT
where:
- q is the heat energy absorbed or released (in calories),
- m is the mass of the substance (in grams),
- c is the specific heat capacity (in cal/g°C), and
- ΔT is the change in temperature (in °C).
Here, we are given that:
- q = 10.0 calories,
- m = 3.1 grams, and
- ΔT = 17.9°C.
Now, we need to solve for c:
c = q / (mΔT)
Plugging in the known values:
c = 10.0 cal / (3.1 g × 17.9°C)
c = 10.0 cal / (55.49 g°C)
c ≈ 0.1801 cal/g°C
The specific heat capacity of the ring is approximately 0.1801 cal/g°C.