Question

A blue-light photon has a wavelength of 4.80 × 10-7 meter. What is the energy of the photon?

Answer 1

The energy of a photon is presented in the equation of E = hc/gamma where E is the energy of the photon, hc is 1.99x10^-25 joules – meter and gamma is the wavelength of the photon. Since you are given a blue-light photon with a wavelength of 4.80 × 10-7 meter, plug in the values to the energy equation and you will get 4.15x10^-19 joules.

Answer 2

`Energy = 4.125 * 10^(-19) J`

`Energy = 2.6 eV`

Step-by-step explanation:

As we know that energy associated with a photon is given by

`Energy = (hc)/(\lambda)`

here we know that

`h = 6.6 * 10^(-34)`

c = speed of light

now we have

`\lambda = 4.80 * 10^(-7) m`

now we will have

`E = ((6.6 * 10^(-34))(3 * 10^8))/(4.80 * 10^(-7))`

`E = 4.125 * 10^(-19) J`

now we can also convert it into electron volt

`E = (4.125 * 10^(-19))/(1.6 * 10^(-19)) = 2.6 eV`