402,644 views
35 votes
35 votes
Which counterexample shows that the following conjecture is false? Every perfect square number has exactly three factors. F The factors of 2 are 1, 2.G The factors of 4 are 1, 2, 4, H The factors of 8 are 1,2,4,8,I The factors of 16 are 1, 2, 4, 8, 16,

User Adam Seabridge
by
3.3k points

1 Answer

19 votes
19 votes

hello

from the options given,

G and I are perfect squares with the exception of F and H

F is not a perfect square which is the perfect square of 2

G is a perfect square and it's the perfect square of 2

H is not a perfect square

I is a perfect square and it is the perfect square of 16

the answer to this question is I

User Keyv
by
2.8k points