Register
how many grams of ca(po4)2 would be produced when 1.5 grams of (nh4)3po4 is reacted with an excess of ca(oh)2
40.8k views
0 votes
how many grams of ca(po4)2 would be produced when 1.5 grams of (nh4)3po4 is reacted with an excess of ca(oh)2

User Sleeplessnerd
by
6.5k points

1 Answer

5 votes
Molar mass :

(NH₄)₃PO₄ = 149.0 g/mol

Ca₃(PO₄)₂ = 310.17 g/mol

2 (NH₄)₃PO4 + 3 Ca(OH)₂= Ca₃(PO₄)₂ + 6 NH₄OH

2 * 149 g --------- 310.17 g
1.5 g -------------- ?

mass = 1.5 * 310.17 / 2 * 149

mass = 465.255 / 298

= 1.561 g of Ca₃(PO₄)₂

hope this helps!

User Stuart Siegler
by
6.6k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.1m questions

9.5m answers

Other Questions

Key facts of covalent bonding
What conditions must be met in order for a reaction to be considered exothermic?
What functional groups are present in acetaminophen?
Which anion will form a precipitate with Ca2+
Classify these substances as acidic, basic, or neutral: Vinegar, baking soda, tomato juice, sugar
Link Copied!