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Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?

f(x) = –x2 – 8x – 16

f(x) = –x2 + 8x – 16

f(x) = –x2 – 8x + 16

f(x) = –x2 + 8x + 16

2 Answers

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Answer:

The answer is B. Just took the test.

Explanation:

User VeenarM
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2 votes
Hello,

f(x)=-(x-4)²=-(x²-8x+16)=-x²+8x-16

Answer B
User MWinstead
by
7.9k points

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