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How do you solve for sinxcos2x+cosxsin2x=0 ?
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4 votes
How do you solve for sinxcos2x+cosxsin2x=0 ?

User Ian Lotinsky
by
8.2k points

2 Answers

7 votes
The answer is x = n p i divided by 3
User Joe Gasewicz
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8.3k points
6 votes
LHS is nothing but (using sin (a+b) = sin a cos b + cos a sin b)

sin (x+2x) = sin 3x = 0

so 3x = npi
or
x = npi/3

User ChrisZZ
by
7.8k points
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