In simplified exponential notation, the expression a²· a^ (-3) · a =A 1/aB 0C 1

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14 votes

Solution

Note: Law of Indices

$\begin{gathered} a^m* a^n=a^(m+n) \\ and \\ a^0=1 \end{gathered}$

To solve the problem

$\begin{gathered} a^2* a^(-3)* a=a^2* a^(-3)* a^1 \\ a^2* a^(-3)* a=a^(2-3+1) \\ a^2* a^(-3)* a=a^0 \\ a^2* a^(-3)* a=1 \end{gathered}$

Therefore, the answer is

Karthik Bollisetti answered Mar 25, 2023

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