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Solve the system of equations 3y+2z=12 and y-z=9
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5 votes
Solve the system of equations 3y+2z=12 and y-z=9

User Su Llewellyn
by
8.1k points

1 Answer

7 votes
mulitply second equation by 2 and add to first

3y+2z=12
2y-2z=18 +
5y+0z=30

5y=30
divide 5
y=6

sub back
y-z=9
6-z=9
minus 6
-z=3
times -1
z=--3

x=-3
y=6
User Adam Stevenson
by
7.8k points
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