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What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?

User The Demz
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1 Answer

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an=a1(r)^(n-1) is it

common ratio is r
24 is 3rd term
a3=a1(6)^(3-1)=24
a1(6)^2=24
a1(36)=24
divide boh sides by 36
a1=2/3

therefor

a_(n)=a_(1)(6)^(n-1)

User AnthonyY
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