Question

2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many grams of KI are required to produce 1.2g of PbI2.

Answer 1

Molar mass KI = 166.0028 g/mol and Pbl₂ = 461.0089 g/mol

2 Kl + Pb(NO₃)₂ ------> 2 KNO₃ + Pbl₂

2 x 166.0028 g ---------> 461.0089 g
? g KI -------------> 1.2 g

Mass KI = 1.2 x 2 x 166.0028 / 461.0089

Mass KI = 398.40672 / 461.0089

Mass KI = 0.86 g

hope this helps!