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A circuit is supplied with 30 VDC and contains three resistors connected in series. The value or R1 is 80 , the value of R2 is 1,000 , and the value of R3 is 4,200 . What is the voltage drop across R2?

1 Answer

7 votes
The answer is 5.68 Volts.

So givens are electric supply of 30 VDC and the values of 3 resistors.

Given:
E= 30 VDC
R1 = 80 Ohms
R2 = 1000 Ohms
R3= 42000 Ohms

And what we are looking for is the voltage on the second resistor.
First we have to get the current of the circuit.

I = E/(R1+R2+R3)
I = 30 / (80+1000+4200)
I = 30 / (5280)
I = 0.00568 A

Then get the voltage V = I x R

V = 0.00568 x 1000
V = 5.68 V
User Bach Vu
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