Question

Using special products what is (wx-y)^2

Answer 1

I believe it is wx^2 - 2ywx + y^2

Explanation:

seperated into (wx-y)(wx-y) and used FOIL

Answer 2

i think that supposed to be (wx - y^2)^2?

If so, multiply using FOIL:

First: wx * wx = w^2x^2

Outside: wx * -y^2 = -wxy^2

Inside: -y * wx = -wxy^2

Last: -y^2 * -y^2 = y^4

Combine w^2x^2 - 2wxy^2 + y^4