Final answer:
To calculate the mass of glucose in a 75.0 mL of a 1.75 M solution, convert the volume to liters, use the molarity to find moles, and then multiply the moles by glucose's molar mass to get the mass, which is 23.64 g.
Step-by-step explanation:
To determine the mass of glucose in a 75.0 mL of a 1.75 M glucose solution, we will use the formula for molarity which relates moles of solute to the volume of solution in liters: Molarity (M) = moles of solute (mol) / volume of solution (L).
Firstly, we need to convert the volume from milliliters to liters: 75.0 mL × (1 L / 1000 mL) = 0.075 L.
Next, we can calculate the amount of moles of glucose: 1.75 M = moles of glucose / 0.075 L which gives us moles of glucose = 1.75 mol/L × 0.075 L = 0.13125 mol.
Finally, to find the mass of glucose, we need the molar mass of glucose, which is approximately 180.16 g/mol. So, the mass of glucose is 0.13125 mol × 180.16 g/mol = 23.64 g.