416,771 views
12 votes
12 votes
What is the solution to the equation below? 2х 、 x -2 O A. X= 3 O B. x=6 C. X= 4 D. X= 5

User Troy Witthoeft
by
3.4k points

1 Answer

10 votes
10 votes

The given equation is


\frac{\sqrt[]{2x}}{\sqrt[]{x-2}}=2

We will square both sides to cancel the roots


\frac{(\sqrt[]{2x})^2}{(\sqrt[]{x-2)^2}}=(2)^2

Power 2 will cancel the square roots on the left side


(2x)/(x-2)=4

By using cross multiplication

User IMHO
by
2.9k points