Question

How many grams of NH3 can be produced from 4.54 mol of N2 and excess H2?

Answer 1

First we make a Balanced Chemical Equation:


`N_(2) + 3H_(2) = 2NH_(3)`


Now we can solve using the Mole Ratio:

4.54 mol N2 × 2 / 1 × 17.04 g/mol NH3
= 154.72 g

If you need further clarification, feel free to comment.