Answer:
Let C be the position of a person in a helicopter. A,B be two objects lying opposite to each other on either bank of a river.
Let AD=x,BD=y
In ΔACD,
⇒tan30
o
=
AD
CD
⇒
3
1
=
x
700
⇒x=130
3
⇒x=130(1.732)=1212.4
∴ the width of the river =x+y
=1212.4+130
=1342.4m
Explanation: