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The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is 14.8099 units, and its area is square units.
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The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is

14.8099
units, and its area is
square units.

User Angelo Chrysoulakis
by
7.2k points

2 Answers

5 votes
the perimeter is 22.81 you can use GeoGebra to do this easily.
The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is-example-1
User Vivek Kodira
by
7.0k points
3 votes

Perimeter= 22.81

Area= 24

GO PLATO USERS

User Saumilsdk
by
7.1k points
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