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In quadrilateral ABCD, angle A=(4x+10), Angle B=108, angle C= 3x, and angle D=67. Solve for x.

In quadrilateral ABCD, angle A=(4x+10), Angle B=108, angle C= 3x, and angle D=67. Solve for x.
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3 votes
In quadrilateral ABCD, angle A=(4x+10), Angle B=108, angle C= 3x, and angle D=67. Solve for x.

User Polity
by
8.0k points

1 Answer

4 votes
as the sum of angels in quadrilateral = 360°
so , A+B+C+D = 360
hence, x = 25
User Chrisdrobison
by
9.4k points
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