Question

What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 ml container at 58c?

Answer 1

T = 58 + 273.15 = 331.15

R = 0.082 atm

V = 250.0 mL / 1000 = 0.25 L

P = n x R x T / V

P = 2.48 x 0.082 x 331.15 / 0.25

P = 67.342 / 0.25

P = 269.368 atm

hope this helps!

Answer 2

Step-by-step explanation:

The given data is as follows.

V = 250.0 ml, T = 58^{o}C = 58 + 273 = 331 K

n = 2.48 moles, P = ? , R = 0.082 atm L /K mol

Therefore, calculate the pressure using ideal gas equation as follows.

PV = nRT

P =
`(nRT)/(V)`

=
`(2.48 mol * 0.082 atm L/K mol * 331 K)/(250.0 ml)`

= 0.269 atm

Thus, we can conclude that pressure of the given gas is 0.269 atm.