Question

use the counting principle to find the probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0 to 9

Answer 1

The total feasible numbers are: 10*10*10*10*10*10*10*10 = 10^8

The probability is 1/10^8

Answer 2

Answer:
`1/10^8`

Explanation:

Here the total numbers are 10 ( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

Since, the probability of choosing one number =
`(1)/(10)`

Therefore, the probability of choosing 8 numbers =

`(1)/(10)*(1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)*` ( because there is no replacement)

=
`(1)/(10^8)`