Final answer:
An even number that has a 7 in the hundreds place, has an odd number in the thousands place, and is a multiple of 10 could be 5700.
Step-by-step explanation:
To write an even number that has a 7 in the hundreds place, has an odd number in the thousands place, and is a multiple of 10, we need to consider each condition one by one. First, any even number that is a multiple of 10 will end with a 0. Since we need a 7 in the hundreds place, our number will have 70 as the last two digits. Now, we need an odd number in the thousands place; let's choose 5 as an example of an odd number. Combining these elements, a number that meets all the conditions could be 5700.