Question

a car accelerates uniformly from rest to a speed of 23.7 km/h in 6.5 seconds. find the distance the car travels during this time.

Answer 1

The distance traveled by the car during the given time can be found using the formula: distance = initial velocity * time + (1/2) * acceleration * time^2. By plugging in the given values, we can calculate that the car travels a distance of 20.708 meters.

Step-by-step explanation:

The distance that the car travels during the given time can be found using the equation:

distance = initial velocity * time + (1/2) * acceleration * time^2

In this case, the car starts from rest, so the initial velocity is 0 km/h.

The acceleration can be found using the formula:

acceleration = (final velocity - initial velocity) / time

Plugging in the values:

acceleration = (23.7 km/h - 0 km/h) / 6.5 s

Now, we can calculate the distance:

distance = 0 km/h * 6.5 s + (1/2) * (23.7 km/h - 0 km/h) / 6.5 s * (6.5 s)^2

Simplifying the equation gives:

distance = (1/2) * (23.7 km/h) * 6.5 s

Converting km/h to m/s:

distance = (1/2) * (23.7 km/h * 1000 m/km) * (1 h/3600 s) * 6.5 s

Calculating the final result:

distance = 20.708 m

Answer 2

`\Delta v=(s)/(t)\\\\ velocity_(final)-velocity_(initial)=(distance)/(time)\\\\ velocity_(initial)=0(km)/(h)\\\\ velocity_(final)=23,7(km)/(h)\\\\time=6,5s=(6,5)/(3600)h\\\\ 23,7-0=(distance)/((6,5)/(3600))\ \ \ |*(6,5)/(3600)\\\\ 23,7*(6,5)/(3600)=distance\\\\distance=0,043km`