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Please solve...Thanks

Please solve...Thanks-example-1

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Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.

Perimeter=40ft

The perimeter of a rectangle is:

P=2l+2w

Since we know the length is 5 and the perimeter is 40, we can solve for the width.

P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w

The width of the fence is 15feet.

User Josh Hrach
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