A man has 43 coins, All nickels, dimes & quarters. He has one more than three times as many dimes as he does nickels and twice as many quarters as he does nickels. How many of each coin does he have ?

asked Jan 27, 2015 33.6k views

3 votes

8.9k points

Please log in or register to add a comment.

3 votes

1 + 3d = n => (n-1) / 3 = d
2n = q
n + d + q = 43
substitute
n + (n-1) / 3 + 2n = 43
n = 13
q = 26
d = 4

ThomasSquall answered Feb 1, 2015

8.0k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers