Answer:
Area = 3,656.6 m²
Explanation:
Area enclosed by the track is composed of two semicircles and a rectangle.
Area = area of two semicircles + area of rectangle
= 2(½*πr²) + L*W
Where,
radius of semicircle (r) = ½of 40 m = 20 m
Length of rectangle (L) = 60 m
Width of rectangle (W) = 40 m
Plug in the values
Area = 2(½*π*20²) + 60*40
Area = 400π + 2,400
Area = 3,656.6 m² (aooroximated to nearest tenth)