From the information given,
the liquid contains 60 oz of solution
a) For the 10% acid solution,
100% = 60 oz
10% = x oz
By cross multiplying,
x = (60 * 10)/100 = 6
The amount of pure acid in 60 oz of 10% acid solution is 6 oz
b) For the 15% acid solution,
100% = 60 oz
15% = x oz
By cross multiplying,
x = (60 * 15)/100 = 9
The amount of pure acid in 60 oz of 15% acid solution is 9 oz
c) For the 30% acid solution,
100% = 60 oz
30% = x oz
By cross multiplying,
x = (60 * 30)/100 = 18
The amount of pure acid in 60 oz of 30% acid solution is 18 oz
d) For the 60% acid solution,
100% = 60 oz
60% = x oz
By cross multiplying,
x = (60 * 60)/100 = 36
The amount of pure acid in 60 oz of 60% acid solution is 36 oz