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If 600.0 ml of air at 20.0 c is heated to 60.0L , what will be its volume

If 600.0 ml of air at 20.0 c is heated to 60.0L , what will be its volume
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If 600.0 ml of air at 20.0 c is heated to 60.0L , what will be its volume

User Riddik
by
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1 Answer

5 votes
p1v1/t1 = p2t2/t2

p is constant
v1=600, t1 =20c=293K
v2=?, t2=60c=333K
temperature must be in Kelvin

do the math
User Lhunath
by
7.4k points
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