Question

Homework: 3.4Score: 0 of 1 ptX 3.4.12Perform the indicated calculation,7C412CA7C412CA(Round to the nearest thousandth as needed.)

Answer 1

we have that

The formula for combinations is

C=n!/[(n-r)!*r!]

so

step 1

Find 7C4

we have

n=7, r=4

substitute

7C4=7!/[(7-4)!*4!]

7C4=7!/[(3)!*4!]

7C4=7*6*5*4!/[(3)!*4!]

simplify

7C4=7*6*5/[(3)!]

7C4=210/6

7C4=35

step 2

Find 12C4

n=12, r=4

substitute

12C4=12!/[(12-4)!*4!]

12C4=12*11*10*9*8!/[(8)!*4!]

simplify

12C4=12*11*10*9/[4!]

12C4=11,880/[24]=495

therefore

7C4/12C4=35/495=0.071

answer is 0.071