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I need help on the question I don’t get it what so ever

I need help on the question I don’t get it what so ever-example-1
User Joelty
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1 Answer

21 votes
21 votes

Answer:


y\text{ = -}(5)/(2)x\text{ + 3}

Step-by-step explanation:

The general equation of a straight line is:


y\text{ = mx + b}

where m is the slope and b is the y-intercept

For the line given, the slope value is 2/5

When two lines are perpendicular, the product of their slopes is -1

Thus, from the slope of the first line, we can get the slope of the second line

Let us call the slope of the second line m2


\begin{gathered} m_2*\text{ }(2)/(5)\text{ = -1} \\ \\ m_2\text{ = -}(5)/(2) \end{gathered}

We have the slope of the second line and a point (2,-2) through which the line passes

We can write the equation of the line using the point-slope form as follows:


\begin{gathered} y-y_1=m(x-x_1) \\ y+\text{ 2 = -}(5)/(2)(x-2) \\ \\ y\text{ + 2 = -}(5)/(2)x\text{ +5} \\ \\ y\text{ = -}(5)/(2)x\text{ + 5-2} \\ \\ y\text{ = -}(5)/(2)x\text{ + 3} \end{gathered}

User Niraj
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