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You have a grain elevator that reaches 28 feet high and sits 32 feet from the base of the grain bin. What is the slope of the elevator? & what angle does the elevator make with the ground?

User David Cary
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1 Answer

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The distance between the base of the elevator and the grain bin, the height of the grain bin, and the distance between the elevator and the distance between the elevator and the top of the grain bin form a right triangle.

To determine the slope of the elevator (marked in the sketch with x) you can use the Pythagorean theorem, which states that the square of the hypothenuse is equal to the sum of the squares of the legs of the triangle:


a^2+b^2=c^2

Where

a and b represent the legs of the triangle

c represents the hypothenuse

For our triangle:

a= 32ft

b= 28ft

c= x


\begin{gathered} 32^2+28^2=x^2 \\ 1024+784=x^2 \\ 1808=x^2 \\ \sqrt[]{1808}=\sqrt[]{x^2} \\ x=4\sqrt[]{113}ft \end{gathered}

Next, to determine the angle of elevation (marked on the sketch with yº) you can use trigonometric ratios. In this case, given that we know the lengths of the side across the angle and the side next to the angle. The trigonometric ratio that relates both sides is the tangent defined as follows:


\tan \theta=(opposite)/(adjacent)

Where

θ represents the angle of interest

opposite refers to the side across the angle

adjacent refers to the side next to the angle

So, the tangent of the angle of elevation can be expressed as:


\begin{gathered} \tan y=(28)/(32) \\ \tan y=(7)/(8) \end{gathered}

Apply the inverse tangent to both sides of the equal sign to determine the measure of the angle:


\begin{gathered} \tan ^(-1)(\tan \theta)=\tan ^(-1)((7)/(8)) \\ \theta=41.18º \end{gathered}

You have a grain elevator that reaches 28 feet high and sits 32 feet from the base-example-1
User Borgleader
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