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What is the Turing point of f(x)=x^2-2x+8
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What is the Turing point of f(x)=x^2-2x+8

User Gareth Luckett
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method1:parabola
y = x^2 - 2x + 8
y-7 = (x-1)^2 ; parabola
turning point is (1,7)

method2:diff
y = x^2 - 2x + 8
y' = 2x -2 = 0 ==> x = 1,
y=7

User Rahul P
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